steve - 1 month ago 7

Scala Question

`object answer {`

def product(f:Int=>Int)(a:Int,b:Int):Int =

if (a>b) 1

else f(a) * product(f)(a+1,b)

product(x=>x*x)(3,4)

def fact(n:Int) = product(x=>x)(1,n)

}

I can answer the result of this execution it like this:

`// 3*3* product(f)(4,4)`

// 3*3 * (4*4) * product(f)(5,4)

// 3*3 * 4*4 * 1

// 3*3 * 4*4

// 144

However I dont I understand this block of code

`product(f)(a+1,b)`

Answer

The block of code `product(f)(a+1,b)`

is a call of method `product`

with arguments: `f`

, `a+1`

and `b`

.

More details:

`product`

is a recursive higher-order function with multiple parameter lists.

- It is recursive since there is a call to itself in its body.
- It is higher-order since it takes a function as an argument (see higher-order functions).
- It has two parameter lists (see currying):
- the first one consist of a single parameter: a function
`f:Int=>Int`

; - the second contains two parameters:
`a: Int`

and`b: Int`

.

- the first one consist of a single parameter: a function

Source (Stackoverflow)

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