I am working on a small program that calculates different things related to orbital mechanics, such as the semi-major axis of an orbit, velocity etc. (No experience in this subject is required to answer this).
Everything worked out well, until I tried to calculate the orbital period (a formula where I had to use Pi):
T = 2π √ a3 / µ (Click for image)
Where T is time in seconds, a is the semi-major axis, and µ is the standard gravitational parameter.
Now, my problem is that my program does not calculate it very precise, as the result of the formula is a bit off; for example: a circular orbit at an altitude of 160km should take approx 88 minutes, but my program tells me an approx of 90 minutes and 37 seconds.
#the standard gravitational parameter of the Earth
gravPara = 3.986004418*10**14
#the semi-major axis of the orbit (the radius of the Earth + the apoapsis and periapsis of your orbit / 2)
semiMajor = (bodyDia + ap + pe) / 2
#formula to calculate orbital period
timeSeconds = (2 * math.pi) * math.sqrt(semiMajor**3 / gravPara)
#making the result appear as minutes and seconds instead of just seconds
timeMinutes = 0
while (timeSeconds > 60):
timeSeconds = timeSeconds - 60
timeMinutes = timeMinutes + 1
#round the variable to store seconds
#print the result
math.pi is a float with 15 decimals: 3.141592653589793
As per chepners comment to your original post, that equates to about the size of an atom when calculating spheres the size of the earth.
So to answer your question: it's not