JimS JimS - 10 months ago 55
Bash Question

comparing dates using awk in bash

So I have a file and each line has some info and a date (birthday). And I want to print the lines with dates after a given date. I use this awk command

awk -F '|' 'FNR>1 $dateA<=$5 {print $1" "$2" "$3" "$4" "$5" "$6" "$7" "$8}' $FILE

But it doesnt work properly (all file lines are printed). The dates are in YYYY-MM-DD format so alphabetical order is also chronological.

EDIT: Some lines from the input file

1099511633435|Smith|Jack|male|1981-04-19|2010-05-26T03:45:11.772+0000||Internet Explorer

Answer Source

As it was said by others, a variable in single quotes will not be expanded by the shell. Awk will see the name of the variable, not its value.

One possible solution is to do this (assuming comparing strings is correct):

infile='file to read values from'
awk -F '|' -v dateA="$dateA" '{if (FNR>1 && dateA<=$5) {print}}' "$infile"