user2836478 user2836478 - 1 year ago 64
C++ Question

Vector addition in C++ is not coming out exactly right

I am trying to add one vector to another vector in my C++ program and addition is coming out inexact.

This is the vector class (using cmath library):

class Vec{
float dir, mag;
Vec(float dir, float mag){
this->dir = dir;
this->mag = mag;
float getX(){
return cos(dir)*mag;
Vec operator + (Vec v2){
float triangleX = cos(dir)*mag+cos(v2.dir)*v2.mag;
float triangleY = sin(dir)*mag+sin(v2.dir)*v2.mag;
return Vec(atan2(triangleY, triangleX), sqrt(pow(triangleX,2)+pow(triangleY,2)));

And this is the main function:

int main(){
Vec v1(0, 3); // 0º
Vec v2(3.14159265/2, 3); // 90º
Vec v3(3.14159265, 3); // 180º
std::cout<<"v1: "<<v1.getX()<<std::endl;
std::cout<<"v1+v2: "<<(v1+v2).getX()<<std::endl;
std::cout<<"v1+v3: "<<(v1+v3).getX()<<std::endl;
return 0;

And this is the output:

v1: 3
v1+v2: 2.99999976158142
v1+v3: 1.98007097372034e-014

As you can see, the first output v1 is fine.

The second output is the addition of 0 degrees and 90 degrees (an angle that was not supposed to affect the x component), his x component is close to 3, but not exactly 3.

The third output is the addition of 2 opposite vectors with the same magnitude, it was supposed to be 0, but it is not what shows here.

What is causing these strange additions and how do I make them exact?

Answer Source

The basic problem you're having is one of limited precision of float and the value of pi that you're using. Moving to a double will help, and since you're already including <cmath> you should use the value there which is M_PI and is accurate to at least the precision of double. With that said, you're still not going to get exact answers with this approach. (The answer from alain does a good job of explaining why.)

There are some improvements that could be made. One is a neat trick using a C++11 feature which is "user-defined string literals." If you add this definition to your code:

constexpr long double operator"" _deg(long double deg) {
    return deg*M_PI/180;

You can now append _deg to any long double literal and it will automatically be converted to radians at compile time. Your main function would then look like this:

int main(){
    Vec v1(0.0_deg, 3); 
    Vec v2(90.0_deg, 3); 
    Vec v3(180.0_deg, 3); 
    // ...

The next thing you could do would be to store the x and y coordinates and only do the trigonometric manipulations when needed. That version of Vec might look like this:

class Vec{
    double x,y;
        Vec(double dir, double mag, bool cartesian=false) : x(dir), y(mag) {
            if (!cartesian) {
                x = mag*cos(dir);
                y = mag*sin(dir);
        double getX() const {
            return x;
        Vec operator + (const Vec &v2){
            return Vec(x+v2.x, y+v2.y, true);

Note that I've created a bool value for the constructor which tells whether the input is to be a magnitude and direction or an x and y value. Also note that the getX() is declared const because it doesn't alter the Vec and that the argument to operator+ is also a const reference for the same reason. When I make those changes on my machine (a 64-bit machine), I get the following output:

v1: 3
v1+v2: 3
v1+v3: 0
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