RoboCode - 4 months ago 9x

Ruby Question

If there is an array

`array A = ["a","b","c","d"] #Index is [0,1,2,3]`

And it's sorted to.

`array A = ["d","c","b","a"]`

I need an array that returns me the updated index based on the sorted order

`[3,2,1,0]`

I'm trying to find a solution to this ruby

If a is sorted to

`array A = ["d","b","c","a"] #not a pure reverse`

Then the returned index array should be

`[3,1,2,0]`

Answer

You need to create a mapping table that preserves the original order, then use that order to un-map the re-ordered version:

```
orig = %w[ a b c d ]
orig_order = orig.each_with_index.to_h
revised = %w[ d c b a ]
revised.map { |e| orig_order[e] }
# => [3, 2, 1, 0]
```

So long as your elements are unique this will be able to track any shift in order.

Source (Stackoverflow)

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