so my program will require the user to input a phrase WITHOUT punctuation and the program will return its position in the list.
list = input("Enter a phrase without punctuation:")
list = list.split(" ")
list = [element.lower() for element in list]
find=input("what word must be found?")
if find in list:
for find in list:
print("its not in the list.")
i found a way here it is.
sentence =input("phrase to be shortened: ") print (sentence) text = input("Choose a word from the sentence above: ") sentence = sentence.upper() sentence = sentence.split(" ") text = text.upper ()# this makes the text in capital letters def lookfor (text): indexes = [ idx+1 for word, idx in zip(sentence, range(0,len(sentence))) if text == word ] print ("Your word has been found in the sentence at these positions", indexes ) if not indexes: print ("The word that you have typed is not found in the sentence.") lookfor(text)