Superpolock Superpolock - 1 month ago 5
C++ Question

Can you use keyword explicit to prevent automatic conversion of method parameters?

I know you can use C++ keyword 'explicit' for constructors of classes to prevent an automatic conversion of type. Can you use this same command to prevent the conversion of parameters for a class method?

I have two class members, one which takes a bool as a param, the other an unsigned int. When I called the function with an int, the compiler converted the param to a bool and called the wrong method. I know eventually I'll replace the bool, but for now don't want to break the other routines as this new routine is developed.



No, you can't use explicit, but you can do this instead:

class ClassThatOnlyTakesBoolsAndUIntsAsArguments
  void Method(bool arg1);
  void Method(unsigned int arg1);

  // Below just an example showing how to do the same thing with more arguments
  void MethodWithMoreParms(bool arg1, SomeType& arg2);
  void MethodWithMoreParms(unsigned int arg1, SomeType& arg2);

  template<typename T>
  void Method(T arg1);

  // Below just an example showing how to do the same thing with more arguments
  template<typename T>
  void MethodWithMoreParms(T arg1, SomeType& arg2);

Repeat this pattern for every method that takes the bool or unsigned int. Do not provide an implementation for the templatized version of the method.

This will force the user to always explicitly call the bool or unsigned int version.

Any attempt to call Method with a type other than bool or unsigned int will fail to compile because the member is private, subject to the standard exceptions to visibility rules, of course (friend, internal calls, etc.). If something that does have access calls the private method, you will get a linker error.