Elena -3 years ago 99

Python Question

I need the current time with nanosec.

As string

`"%.9f" % float_time`

If I try to write the same time as int

`int(float_time*10**9)`

`from time import time`

float_time = time()

print("float_time:", float_time)

int_nano_time = int(float_time*10**9)

print("int_nano_time:", int_nano_time)

str_nano_time = "%.9f" % float_time

print("str_nano_time:", str_nano_time)

float_time: 1502872986.6536937

int_nano_time: 1502872986653693696

str_nano_time: 1502872986.653693676

`time.monotonic()`

float_time: 536596.296

int_nano_time: 536596296000000

str_nano_time: 536596.296000000

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Answer Source

Both are correct within the IEEE754 double precision of ~15.7 decimal digits. The reason is that the multiples of ten cannot be produced exactly, so while multiplying by `2 ** 10`

is exact, multiplying by `5 ** 10`

will have rounding errors again, and that's why the last numbers differ.

```
'1502872986.653693675994873046875000000000'
>>> "%.30f" % (1502872986.653693676 * 10 ** 9)
'1502872986653693696.000000000000000000000000000000'
```

The hex representations of these 2 floating point numbers are wildly different:

```
>>> (1502872986.653693676 * 10 ** 9).hex()
'0x1.4db4704d00617p+60'
>>> (1502872986.653693676).hex()
'0x1.6650166a9d61ep+30'
```

As for the time returned from the `time()`

call - well it is highly probable that should the computer have a timer that gives a timestamp with high enough precision *any* time value will be between the exact time `time()`

was called and when it returned:

```
>>> (time() - time()) * 10 ** 9
-715.2557373046875
>>> (time() - time()) * 10 ** 9
-953.67431640625
>>> (time() - time()) * 10 ** 9
-953.67431640625
```

your error was 20 nanoseconds, but the time difference between 2 consecutive timestamps returned from `time()`

call is 700-100 nanoseconds on my computer.

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