Anirudh - 11 months ago 121

Java Question

The question is about Solving this problem from codingBat in Java.

**Problem Statement:**

*Given a non-empty array of ints, return a new array containing the elements from the original array that come after the last 4 in the original array. The original array will contain at least one 4. Note that it is valid in Java to create an array of length 0.*

*post4({2, 4, 1, 2}) → {1, 2}*

*post4({4, 1, 4, 2}) → {2}*

*post4({4, 4, 1, 2, 3}) → {1, 2, 3}*

Here is my solution:

`public int[] post4(int[] nums) {`

int lastFour=-1;

int[] post4={};

for(int i=nums.length-1;i>=0;i--)

{

if((nums[i]==4))

{

lastFour=i; //find the index of the last 4 in the array

break;

}

}

int newLen=(nums.length-lastFour)-1;

post4=new int[newLen]; //reassign the post4 array with required length

for(int j=0;j<newLen;j++)

{

post4[j]=nums[lastFour+1]; //assign values from orig. array after last 4

lastFour++;

}

return post4;

}

But I have used 2 loops. It should be solved using at max one loop. Do not use collections or any wrappers classes.

Answer Source

- Before iteration create result array, lets say with length 0.
- Each time you find
`4`

create new result array with size based on index of that`4`

and length of`nums`

to store rest of elements. - If number is not
`4`

place it in result array (don't place if result arrays length is`0`

because it means we didn't find any`4`

yet, or it was last element of`nums`

array).

Here is example solution

```
public int[] post4(int[] nums) {
int[] result = new int[0];
int j = 0;
for (int i = 0; i<nums.length; i++){
if (nums[i] == 4) {
result = new int[nums.length - i-1];
j=0;
}
else
if (result.length>0) result[j++] = nums[i];
}
return result;
}
```