Split a string having colon and store in vector using regex pattern in C++

Question

I want to split the string

"Input\temp.csv:1:14"

separated by colon and store the results in a vector. What should the regex look like? Or do I need an entirely different approach?

sInpFileName = "Input\temp.csv:1:14";



regex colon(?);

vector<string> MyVector(sregex_token_iterator(sInpFileName.begin(), sInpFileName.end(), colon, 1), sregex_token_iterator());

MyVector should have three element as

Input\temp.csv

1

14

Answer 1

This should work:

[live]

std::string sInpFileName = "Input\\temp.csv:1:14";

std::regex re{"([^:]+)"};
std::regex_token_iterator<std::string::iterator> it{sInpFileName.begin(), sInpFileName.end(), re, 1};
decltype(it) end{};
while (it != end) std::cout << *it++ << std::endl;

Split a string having colon and store in vector using regex pattern in C++

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