LiraNuna - 3 months ago 24

C++ Question

While writing some test cases, and some of the tests check for the result of a NaN.

I tried using

`std::isnan`

`Assertion `std::isnan(x)' failed.`

After printing the value of

`x`

`-nan`

After trying to use the fact that

`NaN != NaN`

`assert(x == x)`

Making my own

`isNaN`

How can I check for both equality of NaN

Answer

This is embarrassing.

The reason the compiler (GCC in this case) was optimising away the comparison and `isnan`

returned `false`

was because someone in my team had turned on `-ffast-math`

.

From the docs:

-ffast-math Sets -fno-math-errno, -funsafe-math-optimizations, -fno-trapping-math, -ffinite-math-only, -fno-rounding-math, -fno-signaling-nans and fcx-limited-range. This option causes the preprocessor macro __FAST_MATH__ to be defined. This option should never be turned on by any -O option since it can result in incorrect output for programs which depend on an exact implementation of IEEE or ISO rules/specifications for math functions.

Notice the ending sentence - `-ffast-math`

is unsafe.