C Question

C - How do I receive a bit from a bit field as a parameter in a function?

I have a bit field defined like that (it is from a microcontroller library, so it looks a bit different):

typedef union {
byte Byte;
struct {
byte PTAD0 :1;
byte PTAD1 :1;
byte PTAD2 :1;
byte PTAD3 :1;
byte PTAD4 :1;
byte PTAD5 :1;
byte :1;
byte :1;
} Bits;
extern volatile PTADSTR _PTAD @0x00000000;
#define PTAD _PTAD.Byte
#define PTAD_PTAD0 _PTAD.Bits.PTAD0
#define PTAD_PTAD1 _PTAD.Bits.PTAD1
#define PTAD_PTAD2 _PTAD.Bits.PTAD2
#define PTAD_PTAD3 _PTAD.Bits.PTAD3
#define PTAD_PTAD4 _PTAD.Bits.PTAD4
#define PTAD_PTAD5 _PTAD.Bits.PTAD5

So. Let's say that i want a function that sets a bit, like that:

void setbit(bit Bit) {
Bit = 1;

Of course, the "bit" declaration doesn't work. I would like a declaration that I could use


and it would set this bit. I could do

void setbit(byte Byte, byte number) {
Byte |= 1<<(number);

and send


That works perfectly, but... that's not what I want, cause I want to do something like Arduino's libraries. Anyone has any idea how to do that in the way I prefered?

Answer Source
  1. C is a pass-by-value language, so even if you could do:

    void setbit(bit Bit) {
         Bit = 1;

    it would be a no-op.

  2. You can do what you're trying with a function-like-macro:

    #define setbit(x) do { (x) = 1; } while(0)

    If you call this macro with PTAD_PTAD5, it should work like you expect.