Varrian Varrian - 1 year ago 165
C Question

Is function return an array possible in Vivado HLS?

A function like tha:

int * getRandom( ) {

static int r[10];
int i;

/* set the seed */
srand( (unsigned)time( NULL ) );

for ( i = 0; i < 10; ++i) {
r[i] = rand();
printf( "r[%d] = %d\n", i, r[i]);

return r;

Is this one possible to be used in Vivado HLS. If possible, how can I initialize a array without known size because I cannot use
any more.

Answer Source

Converting comments into an answer.

You cannot, in standard C, return an array from a function — you can return a pointer OK (so the code shown is permissible, though it clearly has re-entrancy and threading issues). If you can't use static or malloc() et al, then you need to pass the array to the function for it to fill in instead of returning the array. Then it is the caller's responsibility to allocate the space.

See also srand() — why call it only once.

So you mean I can set a global array as function arguments and give value to each element so I can get the array without using static and malloc?

Yes, or a local array, or an any-other-type of array you care to think of. I think the appropriate implementation might be:

void getRandom(int n_vals, int *i_vals)
    for (int i = 0; i < n_vals; i++)
        i_vals[i] = rand();

but the possible variations are legion. You can reinstate the printing if you really want it; you can even call srand() if you really want to (but you should only call that once). You can then use it like:

void somefunc(void)
    int data[20];
    getRandom(15, data);
    …use data…;


static int data[20];

void somefunc(void)
    getRandom(18, data);
    …use data…;

or other variants (such as not using static in front of the file-scope definition of data — converting it into a global variable). (Yes, you'd probably use 10 as in the question, or 20 as the amount of space in the array — but 15 and 18 are also OK values in their context.)