Dirigible - 5 months ago 16

R Question

I've written a simple correlation function that takes in three variables. "A" and "B" are numerical vectors of equal length, and "n" is the length.

`Corr.fxn <- function(A, B, n){`

Correlation <- (sum((A - mean(A))*(B - mean(B))) / (n-1)) / (sd(A)*sd(B))

return(Correlation)

}

The function works well enough, but I have many vectors I want to process. What's the best way to modify this code to process all "N take 2" unique analyses for my set of vectors "N"?

EDIT:

Example data showing the structure of the vectors:

`A <- c(-1, 0, 1, -1, 0, 1, -1, 0, 1)`

B <- c(1, 1, -1, 0, 1, -1, 0, 0, 1)

...

n <- length(A)

So let's say I have vectors A through Z and I want to modify my code to output a new vector containing all {26 take 2} correlation values.

Answer Source

Here is one possible way you can do it assuming you have a bunch of numeric vectors in a list `v`

as follows:

```
v <- list()
for (i in 1:10) {
v[[i]] <- sample(1:10, 10, replace = TRUE)
}
apply(combn(1:10, 2), 2, function(x) Corr.fxn(v[[x[1]]], v[[x[2]]], length(v[[x[1]]])))
```