Montague27 - 1 year ago 93
Python Question

# python loop x + 1 times in a list of list until number y

What I want is the list in

`num`
loops
`x + 1`
everytime until
`y`
is generated(and loops is stoped), which is a large number.

``````def loop_num(y):
num = []
num.append([1])
num.append([2,3])
num.append([4,5,6])
num.append([7,8,9,10])
... #stop append when y in the appended list
#if y = 9, then `append [7,8]` and `return num`
return num

# something like[[1 item], [2items], [3items], ...]
# the number append to the list can be a random number or ascending integers.
``````

sorry for not clear

Two `itertools.count` objects should do what you want:

``````from itertools import count

def loop_num(y):
counter, x = count(1), count(1)
n = 0
while n < y:
num = []
for i in range(next(x)):
num.append(next(counter))
if num[-1] == y:
break
yield num
n = num[-1]
``````

Output:

``````>>> list(loop_num(100))
[[1],
[2, 3],
[4, 5, 6],
[7, 8, 9, 10],
[11, 12, 13, 14, 15],
[16, 17, 18, 19, 20, 21],
[22, 23, 24, 25, 26, 27, 28],
[29, 30, 31, 32, 33, 34, 35, 36],
[37, 38, 39, 40, 41, 42, 43, 44, 45],
[46, 47, 48, 49, 50, 51, 52, 53, 54, 55],
[56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66],
[67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78],
[79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91],
[92, 93, 94, 95, 96, 97, 98, 99, 100]]
``````
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