David Miró David Miró - 2 years ago 95
Python Question

Creating a numpy array fails when I try to create from an array of QString

If the array has a size of 2x2 or greater all is well, but if the dimension of the row is 1, for example 1x2, numpy does something I did not expect.

How can I solve this?

myarray = np.array([[QString('hello'), QString('world')],
[QString('hello'), QString('moon')]],
print myarray
print myarray.shape
#[[PyQt4.QtCore.QString(u'hello') PyQt4.QtCore.QString(u'world')]
# [PyQt4.QtCore.QString(u'hello') PyQt4.QtCore.QString(u'moon')]]
#(2, 2)

myarray = np.array([['hello'], ['world']], dtype=object)
print myarray
print myarray.shape
# ['world']]
#(2, 1)

myarray = np.array([[QString('hello'), QString('world')]], dtype=object)
print myarray
print myarray.shape
# etc...
#(1, 2, 5, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1)

Answer Source

Try different length strings:

np.array([[QString('hello'), QString('moon')]], dtype=object)`.  

or the create and fill approach to making an object array

A = np.empty((1,2), dtype=object)
A[:] = [QString('hello'), QString('moon')]

I'm not familiar with these objects, but in other cases where we try to build object arrays from lists, it is tricky if the lists are the same length. If QString is iterable, with a .__len__ something similar may be happening.

I'm guessing your first example works because on QString is shorter than the others, not because it is 2x2.

This recent question about making an object array from a custom dictionary class may be relevant: Override a dict with numpy support

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