lyrically wicked - 8 months ago 46

Javascript Question

I have an array of objects, e.g.

`var arr = [`

{"a": "x"},

{"b": "0"},

{"c": "k"},

{"a": "nm"},

{"b": "765"},

{"ab": "i"},

{"bc": "x"},

{"ab": "4"},

{"abc": "L"}

];

Let's say I am only interested in objects whose keys correspond to

`var input = ["ab", "bc"]`

`result[i].length == 2`

`var result = [`

[{"ab": "i"}, {"bc": "x"}],

[{"ab": "4"}, {"bc": "x"}] // or [{"bc": "x"}, {"ab": "4"}]

];

— that is, the order of objects in subarrays is absolutely not important: I am only interested in the fact that each subarray contains two objects —

`{"ab": ...}`

`{"bc": ...}`

If I was interested in

`var input = ["a","a","ab"]`

`var result = [`

[{"a": "x"}, {"a": "nm"}, {"ab": "i"}],

[{"a": "x"}, {"a": "nm"}, {"ab": "4"}]

];

I cannot find the way to achieve the desired result (assuming that

`input.length`

`input.length`

`result.length`

`result.length`

`result`

Answer

Seeing the problem, it kind of look like a cartessian product. In fact, if before operating, the data model is modified a bit, the expected result is, in almost all cases, a cartessian product. However, there's a case (the second example you provided) that needs special treatment. Here's what I did:

- Tweak a bit the model data (this will be done only once) in order to have something suitable to apply cartessian product.
- Treat the "special case" of having more than one parameter requesting the same string.

All the important logic is within `cartessianProdModified`

. The important bits in the code are commented. Hope it helps you with your problem or at least gives you some ideas.

Here's a fiddle and here's the code:

```
var arr = [
{"a": "x"},
{"b": "0"},
{"c": "k"},
{"a": "nm"},
{"b": "765"},
{"ab": "i"},
{"bc": "x"},
{"ab": "4"},
{"abc": "L"},
{"dummy": "asdf"}
];
// Utility function to be used in the cartessian product
function flatten(arr) {
return arr.reduce(function (memo, el) {
return memo.concat(el);
}, []);
}
// Utility function to be used in the cartessian product
function unique(arr) {
return Object.keys(arr.reduce(function (memo, el) {
return (memo[el] = 1) && memo;
}, {}));
}
// It'll prepare the output in the expected way
function getObjArr(key, val, processedObj) {
var set = function (key, val, obj) {
return (obj[key] = val) && obj;
};
// The cartessian product is over so we can put the 'special case' in an object form so that we can get the expected output.
return val !== 'repeated' ? [set(key, val, {})] : processedObj[key].reduce(function (memo, val) {
return memo.concat(set(key, val, {}));
}, []);
}
// This is the main function. It'll make the cartessian product.
var cartessianProdModified = (function (arr) {
// Tweak the data model in order to have a set (key: array of values)
var processedObj = arr.reduce(function (memo, obj) {
var firstKey = Object.keys(obj)[0];
return (memo[firstKey] = (memo[firstKey] || []).concat(obj[firstKey])) && memo;
}, {});
// Return a function that will perform the cartessian product of the args.
return function (args) {
// Spot repeated args.
var countArgs = args.reduce(function (memo, el) {
return (memo[el] = (memo[el] || 0) + 1) && memo;
}, {}),
// Remove repeated args so that the cartessian product works properly and more efficiently.
uniqArgs = unique(args);
return uniqArgs
.reduce(function (memo, el) {
return flatten(memo.map(function (x) {
// Special case: the arg is repeated: we have to treat as a unique value in order to do the cartessian product properly
return (countArgs[el] > 1 ? ['repeated'] : processedObj[el]).map(function (y) {
return x.concat(getObjArr(el, y, processedObj));
});
}));
}, [[]]);
};
})(arr);
console.log(cartessianProdModified(['a', 'a', 'ab']));
```

Source (Stackoverflow)