aselya aselya - 1 year ago 64
Python Question

TypeError on a .join statment

I've set my environmental variable to correspond to

And i keep getting the following error. The goal is for the code to respond to
variables and use them to trigger delimiters in data sets submitted by the user.

Traceback (most recent call last):
File "./qwikifwlistmgr", line 103, in <module>
File "./qwikifwlistmgr", line 94, in delim
e = ".".join(e)

I've made sure all my statements have a return. but right now I'm not sure what else is wrong. I get the feeling its something simple but I just can't see it.

#! /usr/bin/env python
import os
import sys
import re

in_list = sys.argv

def ifw(in_list):
usr_choice = (in_list)[1]
if usr_choice == 'i':
elif usr_choice =='f':
elif usr_choice == 'w':
return in_list

def float_sort(in_list):
float_sort = "test"
sorted_float = "test"
float_sort = in_list[2:]
float_sort = ''.join(float_sort)
#float_sort1 = " ".join(list((re.findall(r"((?<!\S)\d+(?!\S))", float_sort))))
#float_sort2 = ' '.join(list(re.findall(r"(\d+\.\d+)", float_sort)
float_sort = " ".join(re.findall(r"\d*\.\d+|\d+", float_sort))
sorted_float = sorted(float_sort, key=len)
return float_sort

def word_sort(in_list):
word_sort = " 1a "
word_sort = sorted(in_list[2:], key=len) #in_list must be 2 because the program will view usr input as a word
for i in word_sort:
punctuation = '.',',',';','!',' / ','"','?' #strips punctuation from words
if i in punctuation: #removes punctuation
word_sort = word_sort.replace(i," ")
#word_sort= sorted(word_sort, key=lambda L: (L.lower(), L))
word_sort= " ".join(sorted(word_sort, key=lambda L: (L.lower(), L))) #takes string and sorts by length giving priority to upper over lower when tied
sorted_word = " 1a " #left for testing
sorted_word = re.sub("\S+\d\S+", "", word_sort).strip() #removes any word with a number in it
sorted_word = "".join(sorted_word) #joins the results back into a string
return sorted_word

def int_sort(in_list):
int_sort = "3"
in_list = " ".join(in_list[1:]) # takes information from argv and creates a string with it
int_sort = " ".join(list(reversed(re.findall(r"(?<!\S)\d+(?!\S)", in_list))))
# find all looks for a pattern of anything but a space... any number. anything besides a space in the in_list and returns it
#reveresd flips that return backwards
# list turns that into a list and join makes it a string again
return int_sort

def delim(in_list):
z = (ifw(in_list))
x = "screw python"
e = (ifw(in_list))
if x == 'BLANK':
e = ' '.join(ifw(in_list))
return e
elif x =='TAB':
e = ifw(in_list)
e = '\t'.join(e)
return e
elif x =='NL':
e = ifw(in_list)
e = '\n'.join(e)
return e
elif x =='COLON':
e = ifw(in_list)
e = ':'.join(e)
return e
elif x =='COMMA':
e = ifw(in_list)
e = ','.join(e)
return e
elif x =='SEMICOLON':
e = ifw(in_list)
e = ';'.join(e)
return e
elif x =='PERIOD':
e = ".".join(e)
return e
elif x =='SLASH':
e = ifw(in_list)
e = '/'.join(e)
return e
e = ifw(in_list)
return e

Answer Source

The problem is from the ifw function that returns a None if every other branche was taken except the else branch. So the following expression evaluates and assigns a None value to e:

e = ifw(in_list)
e = ".".join(e)

You could fix this by returning an empty iterable, as the default action in the function:

def ifw(in_list):
    if usr_choice == 'i':
        return in_list
    return []

Or return the approriate list of strings in each branch of the if/elif

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