phan - 7 months ago 38

SQL Question

I have a column X which is full of floats with decimals places ranging from 0 (no decimals) to 6 (maximum). I can count on the fact that there are no floats with greater than 6 decimal places. Given that, how do I make a new column such that it tells me how many digits come after the decimal?

I have seen some threads suggesting that I use CAST to convert the float to a string, then parse the string to count the length of the string that comes after the decimal. Is this the best way to go?

Answer

You can use something like this:

```
declare @v sql_variant
set @v=0.1242311
select SQL_VARIANT_PROPERTY(@v, 'Scale') as Scale
```

This will return `7`

.

I tried to make the above query work with a `float`

column but couldn't get it working as expected. It only works with a `sql_variant`

column as you can see here: http://sqlfiddle.com/#!6/5c62c/2

So, I proceeded to find another way and building upon this answer, I got this:

```
SELECT value,
LEN(
CAST(
CAST(
REVERSE(
CONVERT(VARCHAR(50), value, 128)
) AS float
) AS bigint
)
) as Decimals
FROM Numbers
```

Here's a SQL Fiddle to test this out: http://sqlfiddle.com/#!6/23d4f/29

To account for that little quirk, here's a modified version that will handle the case when the float value has no decimal part:

```
SELECT value,
Decimals = CASE Charindex('.', value)
WHEN 0 THEN 0
ELSE
Len (
Cast(
Cast(
Reverse(CONVERT(VARCHAR(50), value, 128)) AS FLOAT
) AS BIGINT
)
)
END
FROM numbers
```

Here's the accompanying SQL Fiddle: http://sqlfiddle.com/#!6/10d54/11

Source (Stackoverflow)