Maverick Maverick - 1 year ago 232
Java Question

CIDR notation and IP range validator pattern

I have a pattern to validate normal IP addresses, that is :

private static final String PATTERN =
"^([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." +
"([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." +
"([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." +
"([01]?\\d\\d?|2[0-4]\\d|25[0-5])$";


And a validate method to check if the input is a valid IP address or not :

private static boolean validate(final String ip){

Pattern pattern = Pattern.compile(PATTERN);
Matcher matcher = pattern.matcher(ip);
return matcher.matches();
}


But, now I need to add validation for CIDR (e.g. 84.240.40.0/24) notation and IP-range without host (e.g. 172.24.105), I tried many different patterns but not getting something concrete. Any suggestions?

Answer Source
Pattern pattern = Pattern.compile("^(([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])\\.){3}([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])(\\/(\\d|[1-2]\\d|3[0-2]))?$");
Matcher matcher = pattern.matcher("84.240.40.0/24");
if (matcher.find()) {
    System.out.println(matcher.group());
}

Output:

84.240.40.0/24

this pattern matches IPv4 address and IPv4 CIDR range if you want tomatch only range ,you should remove last question mark

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