Caroline.py - 1 year ago 66

Python Question

`Fruits = ['apple', 'orange', 'banana', 'kiwi']`

A = [4, 3, 10, 8]

B = {'apple': {'Bill': 4, 'Jan': 3, 'Frank': 5},

'orange': {'Bill': 0, 'Jan': 1, 'Frank': 5},

'banana': {'Bill': 8, 'Jan': 6, 'Frank': 2},

'kiwi': {'Bill': 4, 'Jan': 2, 'Frank': 7}}

I am trying to sum over all the fruits of A and multiply that by B. I am having trouble doing this A is an array of just numbers and B is a dictionary. This is where I am getting confused. I am a new Python user. The numbers in A are in the same position relative to Fruits (the first number in A is the number of apples). Would this involve using sum(A)?

Sorry folks for the lack of details. Here is some clarity. I have fruits and I have numbers of fruits that each person has based on the type. I am wanting to sum all of the values of each fruit type in B such that I get:

`apple = 12`

orange = 6

banana = 16

kiwi = 13

Now, I want to multiple these numbers, by A, but keeping in mind that the first number in A, is apple, then orange, and so on to get a new array:

`Solution = [48,18,160,104] #solution order is apple, orange, banana, kiwi`

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Answer Source

Assuming that you want to multply the sum of the fruits for each person (in `B`

) by the cost in `A`

, you can do the following list comprehension:

```
>>> [cost * sum(B[fruit].values()) for cost, fruit in zip(A, Fruits)]
[48, 18, 160, 104]
```

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