CodingIntrigue CodingIntrigue - 2 months ago 13
Javascript Question

Defer execution for ES6 Template Literals

I am playing with the new ES6 Template Literals feature and the first thing that came to my head was a

for Javascript so I went about implementing a prototype:

String.prototype.format = function() {
var self = this;
arguments.forEach(function(val,idx) {
self["p"+idx] = val;
return this.toString();
console.log(`Hello, ${p0}. This is a ${p1}`.format("world", "test"));


However, the Template Literal is evaluated before it's passed to my prototype method. Is there any way I can write the above code to defer the result until after I have dynamically created the elements?


I can see three ways around this:

  • Use template strings like they were designed to be used, without any format function:

    console.log(`Hello, ${"world"}. This is a ${"test"}`);
    // might make more sense with variables:
    var p0 = "world", p1 = "test";
    console.log(`Hello, ${p0}. This is a ${p1}`);
    // or even function parameters for actual deferral of the evaluation:
    const welcome = (p0, p1) => `Hello, ${p0}. This is a ${p1}`;
    console.log(welcome("world", "test"));
  • Don't use a template string, but a plain string literal:

    String.prototype.format = function() {
        var args = arguments;
        return this.replace(/\$\{p(\d)\}/g, function(match, id) {
            return args[id];
    console.log("Hello, ${p0}. This is a ${p1}".format("world", "test"));
  • Use a tagged template literal. Notice that the substitutions will still be evaluated without interception by the handler, so you cannot use identifiers like p0 without having a variable named so. This behavior may change if a different substitution body syntax proposal is accepted (Update: it was not).

    function formatter(literals, ...substitutions) {
        return {
            format: function() {
                var out = [];
                for(var i=0, k=0; i < literals.length; i++) {
                    out[k++] = literals[i];
                    out[k++] = arguments[substitutions[i]];
                out[k] = literals[i];
                return out.join("");
    console.log(formatter`Hello, ${0}. This is a ${1}`.format("world", "test"));
    // Notice the number literals: ^               ^