Jacco Jacco - 3 months ago 6
PHP Question

How to get the path of a derived class from an inherited method?

How to get the path of the current class, from an inherited method?

I have the following:

<?php // file: /parentDir/class.php
class Parent {
protected function getDir() {
return dirname(__FILE__);
}
}
?>


and

<?php // file: /childDir/class.php
class Child extends Parent {
public function __construct() {
echo $this->getDir();
}
}
$tmp = new Child(); // output: '/parentDir'
?>


The
__FILE__
constant always points to the source-file of the file it is in, regardless of inheritance.

I would like to get the name of the path for the derived class.

Is there any elegant way of doing this?

I could do something along the lines of
$this->getDir(__FILE__);
but that would mean that I have to repeat myself quite often. I'm looking for a method that puts all the logic in the parent class, if possible.

Update:

Accepted solution (by Palantir):

<?php // file: /parentDir/class.php
class Parent {
protected function getDir() {
$reflector = new ReflectionClass(get_class($this));
return dirname($reflector->getFileName());
}
}
?>

Answer

This will get you the dirname the class Child is defined on. You can get the class name of an object with get_class():)

$reflector = new ReflectionClass("Child");
$fn = $reflector->getFileName();
return dirname($fn);
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