knd15 - 1 year ago 109

Python Question

This is my code:

`def sum_even(a, b):`

count = 0

for i in range(a, b, 1):

if(i % 2 == 0):

count += [i]

return count

An example I put was print(sum_even(3,7)) and the output is 0. I cannot figure out what is wrong.

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Answer Source

Your indentation is off, it should be:

```
def sum_even(a, b):
count = 0
for i in range(a, b, 1):
if(i % 2 == 0):
count += i
return count
```

so that `return count`

doesn't get scoped to your for loop (in which case it would return on the 1st iteration, causing it to return 0)

(And change `[i]`

to `i`

)

**NOTE:** another problem - you should be careful about using `range`

:

```
>>> range(3,7)
[3, 4, 5, 6]
```

so if you were to do calls to:

`sum_even(3,7)`

`sum_even(3,8)`

right now, they would both output `10`

, which is incorrect for sum of even integers between 3 and 8, inclusive.

What you really want is probably this instead:

```
def sum_even(a, b):
return sum(i for i in range(a, b + 1) if i % 2 == 0)
```