Avijit Dasgupta - 11 months ago 147

Python Question

I am trying to extract patches of fixed size centered at some given position (x,y). The code is given below-

`for i,j in zip(indices[0],indices[1]):`

patches.append(

x[None,

i-int(np.floor(patch_size/2.0)):i+int(np.floor(patch_size/2.0))+1,

j-int(np.floor(patch_size/2.0)):j+int(np.floor(patch_size/2.0))+1])

Variable

`indices`

`indices.shape=(2,770)`

`x`

But this code is taking 25s seconds time. Can anyone tell me how to make this work faster? or any other alternatives if you can suggest it would be of great help.

Answer

Assuming you are dealing with near-boundary indices separately, as otherwise you would have different shaped patches, let us suggest ourselves a vectorized approach making use `broadcasting`

together with some knowledge about `linear-indexing`

. Posted below is an implementation to go with that philosophy to give us a `3D`

array of such patches -

```
m,n = x.shape
K = int(np.floor(patch_size/2.0))
R = np.arange(-K,K+1)
out = np.take(x,R[:,None]*n + R + (indices[0]*n+indices[1])[:,None,None])
```

Let's do a sample run on a minimal input case with input image `x`

of `(8,10)`

and indices are such that the desired patches don't extend beyond the boundaries of the input image. Then, run the original and proposed approaches for verification. Here we go -

1] Inputs :

```
In [105]: # Inputs
...: x = np.random.randint(0,99,(8,10))
...: indices = np.array([[4,2,3],[6,3,7]])
...:
```

3] Original approach with output :

```
In [106]: # Posted code in the question ...
In [107]: patches[0]
Out[107]:
array([[[92, 21, 84],
[10, 52, 36],
[ 5, 62, 61]]])
In [108]: patches[1]
Out[108]:
array([[[71, 76, 75],
[80, 32, 55],
[77, 62, 42]]])
In [109]: patches[2]
Out[109]:
array([[[16, 88, 31],
[21, 84, 51],
[52, 36, 3]]])
```

3] Proposed approach with output :

```
In [110]: # Posted code in the solution earlier ...
In [111]: out
Out[111]:
array([[[92, 21, 84],
[10, 52, 36],
[ 5, 62, 61]],
[[71, 76, 75],
[80, 32, 55],
[77, 62, 42]],
[[16, 88, 31],
[21, 84, 51],
[52, 36, 3]]])
```