studio apk studio apk - 1 month ago 7
Android Question

How to start app when headset connected to phone in java

How could start app or activity when headphone or headset connected to mobile it's possible ? i read some example in another site about broadcast receiver.i'm new in android developing thanks if write example.

private class MusicIntentReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
if (intent.getAction().equals(Intent.ACTION_HEADSET_PLUG)) {
int state = intent.getIntExtra("state", -1);
switch (state) {
case 0:
Toast.makeText(MainActivity.this, "unplug", Toast.LENGTH_SHORT).show();
break;
case 1:
Toast.makeText(MainActivity.this, "plug", Toast.LENGTH_SHORT).show();
break;
default:

}
}



public class MusicIntentReceiver extends WakefulBroadcastReceiver {
public void onReceive(Context ctx, Intent intent) {
if (intent.getAction().equals(Intent.ACTION_HEADSET_PLUG)) {
int state = intent.getIntExtra("state", -1);
switch (state) {
case 0:
Toast.makeText(ctx, "unplug", Toast.LENGTH_SHORT).show();
break;
case 1:
Toast.makeText(ctx, "plug", Toast.LENGTH_SHORT).show();
break;
}
}
}
}


but this code work when application is running.

Answer

try this permission to your manifest file.

<receiver
    android:name="AudioJackReceiver"
    android:enabled="true"
    android:exported="true" >
    <intent-filter>
        <action android:name="android.intent.action.HEADSET_PLUG" />
    </intent-filter>
</receiver>
Comments