displayname displayname - 1 year ago 81
Python Question

How to feed a placeholder?

I am trying to implement a simple feed forward network. However, I can't figure out how to feed a

Placeholder
. This example:

import tensorflow as tf

num_input = 2
num_hidden = 3
num_output = 2

x = tf.placeholder("float", [num_input, 1])
W_hidden = tf.Variable(tf.zeros([num_hidden, num_input]))
W_out = tf.Variable(tf.zeros([num_output, num_hidden]))
b_hidden = tf.Variable(tf.zeros([num_hidden]))
b_out = tf.Variable(tf.zeros([num_output]))

h = tf.nn.softmax(tf.matmul(W_hidden,x) + b_hidden)

sess = tf.Session()

with sess.as_default():
print h.eval()


Gives me the following error:

...
results = self._do_run(target_list, unique_fetch_targets, feed_dict_string)
File "/usr/local/lib/python2.7/dist-packages/tensorflow/python/client/session.py", line 419, in _do_run
e.code)
tensorflow.python.framework.errors.InvalidArgumentError: You must feed a value for placeholder tensor 'Placeholder' with dtype float and shape dim { size: 2 } dim { size: 1 }
[[Node: Placeholder = Placeholder[dtype=DT_FLOAT, shape=[2,1], _device="/job:localhost/replica:0/task:0/cpu:0"]()]]
Caused by op u'Placeholder', defined at:
File "/home/sfalk/workspace/SemEval2016/java/semeval2016-python/slot1_tf.py", line 8, in <module>
x = tf.placeholder("float", [num_input, 1])
...


I have tried

tf.assign([tf.Variable(1.0), tf.Variable(1.0)], x)
tf.assign([1.0, 1.0], x)


but that does not work apparently.

Answer Source

To feed a placeholder, you use the feed_dict argument to Session.run() (or Tensor.eval()). Let's say you have the following graph, with a placeholder:

x = tf.placeholder(tf.float32, shape=[2, 2])
y = tf.constant([[1.0, 1.0], [0.0, 1.0]])
z = tf.matmul(x, y)

If you want to evaluate z, you must feed a value for x. You can do this as follows:

sess = tf.Session()
print sess.run(z, feed_dict={x: [[3.0, 4.0], [5.0, 6.0]]})

For more information, see the documentation on feeding.

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