user1681664 - 2 years ago 126
Python Question

Python Coin change SO CLOSE

I am doing the coin-change problem. I have finished the problem in that it prints out how many coins I need to make the least amount of change possible, but how do I change my program so that it also prints those coins??

Here is a sample

`I/O`
:

input:
`coin_change(48, [1, 5, 10, 25, 50])`

output:
`[6, [25, 10, 10, 1, 1, 1]]`

Currently my code only returns the
`6`
.

by the way, this must be done with recursion only. no loops are allowed

Code:

``````def change(C, V):
def min_coins(i, aC):
if aC == 0:
return 0
elif i == -1 or aC < 0:
return float('inf')
else:
return min(min_coins(i-1, aC), 1 + min_coins(i, aC-V[i]))
return min_coins(len(V)-1, C)
``````

A different version of your program:

``````def change(C, V, res=None):
res = [] if res is None else res
if len(V) == 0:
return len(res), res
maxx = max(V)
V.remove(maxx)
ans = C//maxx
if ans == 0 and maxx < C :
res += [maxx] * ans
return len(res), res
else:
res += [maxx] * ans
return  change(C % maxx, V, res)

print change(48,[1, 5, 10, 25, 50])
print change(30,[25, 10, 2, 3, 1])
``````

output:

``````(6, [25, 10, 10, 1, 1, 1])
(3, [25, 3, 2])
``````

PS: I'll add an explanation if you want.

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