Size of multi dimensional array

Question

I was trying to get the size of a multidimensional array and wrote code in C as shown below.

#include <stdio.h>



char b[3][4];



int main(void){

    printf("Size of array b[3]=%d\n", sizeof(b[3]));  

    printf("Size of array b[2]=%d\n", sizeof(b[2]));

    printf("Size of array b[5]=%d\n", sizeof(b[5]));



    return 0;

}

In all above three print statements, I am getting size equal to 4. Can someone explain how

sizeof

works in case of a multi-dimensional array? Why is the output the same in the third print?

Recommended for you: Get network issues from WhatsUp Gold. Not end users.

Answer 1

b is a 2D character array of rows 3 and columns 4.

So, if you take sizeof(b) you will get 12.

b[0] (and b[i] in general) has a type of a 1D character array of size 4. So. if you take sizeof (b[0]) you will get 4.

b[0][0] (and b[i][j] in general) has a type of char. So if you take sizeof (b[0][0]) you will get 1.

sizeof does not depend on the array index. The type remains the same even for b[0] and b[100], even though it might be out of range of the memory of the array.

Size of multi dimensional array

Sign up