I have large dump of .json files that are sorted by their ID like this: for example TRAMGJJ128F421487E.json is sorted in files based on 3rd - 5th letters so this would be in directory: ../A/M/G/TRAMGJJ128F421487E.json
My question is: how do I open the right file based on given ID?
There are A-Z/A-Z/A-Z/ files in every directory
Can't you just work it out by splitting strings?
base = "/" # Your base directory here json_file = 'TRAMGJJ128F421487E.json' # Input ID folder_one, folder_two, folder_three = json_file[2:5] filename = os.path.join(base, folder_one, folder_two, folder_three, json_file)
And in Python 3.5 you can just unpack an iterable on the fly:
base = "/" # Your base directory here json_file = 'TRAMGJJ128F421487E.json' # Input ID os.path.join(base, *json_file[2:5], json_file)