PHP Question
Getting first weekday in a month with strtotime
I'm trying to figure out the first wednesday of a given month using
strtotimeFor a more general illustration of this problem, see the following code and result:
$mon = strtotime("December 2010 first monday");
$tue = strtotime("December 2010 first tuesday");
$wed = strtotime("December 2010 first wednesday");
$thu = strtotime("December 2010 first thursday");
$fri = strtotime("December 2010 first friday");
$sat = strtotime("December 2010 first saturday");
$sun = strtotime("December 2010 first sunday");
echo strftime("%m/%d/%y", $mon) . "<br>";
echo strftime("%m/%d/%y", $tue) . "<br>";
echo strftime("%m/%d/%y", $wed) . "<br>";
echo strftime("%m/%d/%y", $thu) . "<br>";
echo strftime("%m/%d/%y", $fri) . "<br>";
echo strftime("%m/%d/%y", $sat) . "<br>";
echo strftime("%m/%d/%y", $sun) . "<br>";
Results in:
12/06/10
12/07/10
12/08/10
12/02/10
12/03/10
12/04/10
12/05/10
Notice something? Shouldn't one day of the week coincide with the 1st of the month? But it never does, and instead the second instance of the day, on the 8th, is always returned.
Anyone have an explanation for this?
Answer
I don't have any explanation as I'm also dazzled, but I managed to find out how you get the correct date by omitting the "first", like so:
$ php -r 'echo date("m/d/y", strtotime("December 2010 Wednesday"));'
12/01/10
$ php -r 'echo date("m/d/y", strtotime("December 2010 Thursday"));'
12/02/10
$ php -r 'echo date("m/d/y", strtotime("December 2010 Friday"));'
12/03/10
$ php -r 'echo date("m/d/y", strtotime("December 2010 Saturday"));'
12/04/10
$ php -r 'echo date("m/d/y", strtotime("December 2010 Sunday"));'
12/05/10
$ php -r 'echo date("m/d/y", strtotime("December 2010 Monday"));'
12/06/10
$ php -r 'echo date("m/d/y", strtotime("December 2010 Tuesday"));'
12/07/10
Source (Stackoverflow)