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Python Question

Mylists = [['A B','A B C','A B C D'],['C','D E F','A B']]

How can I get a list like: myli = [['A','B','A','B','C','A','B','C','D'],['C','D','E','F','A','B']]

Here is my code:

`x = []`

myli = []

for item in Mylists:

for i in range(len(item)):

x.extend(item[i].split())

myli.append(x)

Answer

You need to initialize x inside the outer forloop.

Your code

```
Mylists = [['A B','A B C','A B C D'],['C','D E F','A B']]
x = []
myli = []
for item in Mylists:
for i in range(len(item)):
# BUG: since x is not reinitialized, it contains the same old
# memory address that was appended to myli
# extending x means you are modifying the x that you previously appended to myli
# infact, every appended x is the same x !
x.extend(item[i].split())
# appending the same old x, which will inevitably be modified
# in the next iteration
myli.append(x)
```

Correction

```
Mylists = [['A B','A B C','A B C D'],['C','D E F','A B']]
myli = []
for item in Mylists:
x = [] # reinitialize x
for i in range(len(item)):
x.extend(item[i].split())
myli.append(x)
```

Source (Stackoverflow)

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