Arnold Klein - 11 months ago 82

Python Question

I need to find indices of all occurrences of a particular pattern in a string (or numerical vector). For example, given the boolean list (DataFrame):

`z =`

15 False

16 False

17 False

18 False

19 False

20 False

21 False

22 False

23 False

24 True

25 True

26 True

27 False

28 False

29 False

30 False

31 False

32 False

33 False

34 False

35 False

36 True

37 False

38 False

39 False

40 True

41 False

42 False

43 False

44 False

45 True

46 True

47 True

48 False

49 False

I am interested in a function which returns indices of all occurrences of three 'True' in a row, in this example, I should get the index

`>> result = some_function(z)`

>> print result

>> [24, 45]

In matlab it is quite easy with the function strcmp, which does exactly what I need. I am sure that there is a similar function in Python.

I tried to use '

`if ['True', 'True', 'True'] in z`

Answer

I'm assuming here that your inputs are lists:

```
inds =
[15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30,
31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46,
47, 48, 49]
bools =
[False,False,False,False,False,False,False,False,False, True, True,
True,False,False,False,False,False,False,False,False,False, True,
False,False,False, True,False,False,False,False, True, True, True,
False,False]
```

You then want to check for the pattern [True, True, True]

```
pattern = [True, True, True]
```

The required comparison is then done by:

```
[inds[i] for i in range(len(bools)) if bools[i:i+len(pattern)] == pattern ]
```

Returns:

[24, 45]

Source (Stackoverflow)