EnterKEY - 6 months ago 52
C Question

# Initializing "a pointer to an array of integers"

`````` int (*a)[5];
``````

How can we Initialize a pointer to an array of 5 integers shown above.

Is the below expression correct ?

``````int (*a)[3]={11,2,3,5,6};
``````

Suppose you have an array of int of length `5` e.g.

``````int x[5];
``````

Then you can do `a = &x;`

`````` int x[5] = {1};
int (*a)[5] = &x;
``````

To access elements of array you: `(*a)[i]` (== `(*(&x))[i]`== `(*&x)[i]` == `x[i]`) parenthesis needed because precedence of `[]` operator is higher then `*`. (one common mistake can be doing `*a[i]` to access elements of array).

Understand what you asked in question is an compilation time error:

``````int (*a)[3] = {11, 2, 3, 5, 6};
``````

It is not correct and a type mismatch too, because `{11,2,3,5,6}` can be assigned to `int a[5];` and you are assigning to `int (*a)[3]`.

``````int *why = (int[2]) {1,2};
``````int (*a)[5] = (int [][5]){ { 1, 2, 3, 4, 5 } , { 6, 7, 8, 9, 10 } };