poiuytrez poiuytrez - 4 months ago 20
Java Question

External argument to method reference in Java 8

I am looking to pass an external parameter to a method reference:

String prefix = "The number is :";
numbers.forEach(Main::printWithPrefix);

private static void printWithPrefix(Integer number) {
System.out.println(number);
}


I am no idea on how to do it. I am able to do it with a lambda:

String prefix = "The number is :";
numbers.forEach(number -> {
System.out.println(prefix + number);
});


Is it possible to pass an external parameter to a method reference?

Answer

No, you cannot pass a parameter to a method reference. What you can do is create a method which returns a Consumer:

private static Consumer<Integer> printWithPrefix(String prefix) {
    return number -> System.out.println(prefix + number);
}

This then works as a factory for creating a Consumer that you can pass to numbers.forEach:

String prefix = "The number is :";
numbers.forEach(printWithPrefix(prefix));

You can even make it a bit more general, creating a printWithPrefix method that takes a Consumer as an argument so that you could pass in a different one if you'd want to:

private static Consumer<Integer> printWithPrefix(String prefix,
                                                 Consumer<Integer> printer) {
    return number -> {
        System.out.print(prefix);
        printer.accept(number);
    };
}

You could use it, for example, with a printNumber method:

private static void printNumber(Integer number) {
    System.out.println(number);
}

String prefix = "The number is :";
numbers.forEach(printWithPrefix(prefix, Main::printNumber));