So I'm trying to split an arbitrarily long user input integer into a list where each entry is 2 digits, and if the number has an odd amount of integers put the only single digit as the first digit. (Where I will then proceed to put a zero in front of it)
I know that putting user integer input into a list looks like:
userintegerlist = [int(i) for i in str(user_input)]
You can do it with string methods fairly easily, as other answers have already shown. I direct you to the related grouper recipe in itertools.
I want to mention that it may be more efficient to do it with maths:
>>> n = 45346 >>> output =  >>> while n: ... output.append(n % 100) ... n //= 100 ... >>> output = output[::-1] >>> print output [4, 53, 46]