AndyyRi - 3 months ago 11

Python Question

So I'm trying to split an arbitrarily long user input integer into a list where each entry is 2 digits, and if the number has an odd amount of integers put the only single digit as the first digit. (Where I will then proceed to put a zero in front of it)

I know that putting user integer input into a list looks like:

`userintegerlist = [int(i) for i in str(user_input)]`

print userintegerlist

And my input (say it's

`45346`

`[4,5,3,4,6]`

`[4,53,46]`

`68482238`

`[68,48,22,38]`

Is this possible? All the code is in Python by the way.

Answer

You can do it with string methods fairly easily, as other answers have already shown. I direct you to the related grouper recipe in itertools.

I want to mention that it may be more efficient to do it with maths:

```
>>> n = 45346
>>> output = []
>>> while n:
... output.append(n % 100)
... n //= 100
...
>>> output = output[::-1]
>>> print output
[4, 53, 46]
```