it_is_a_literature it_is_a_literature - 1 year ago 112
Bash Question

Cut command to specify the tab as the delimiter

There is a file which the delimiter is tab ,when i use the command

cut -d \t file.txt #or "\t" or "\\t"

I get this message

cut: you must specify a list of bytes, characters, or fields

Try `cut --help' for more information.

How to use the

Answer Source

Cut splits the input lines at the given delimiter (--delimiter, default: tab) and by using the -f (--fields) option you can specify the fields you are interrested in.

echo -e "a\tb\tc" |cut -f 1 # outputs "a"
echo -e "a\tb\tc" |cut -f 2 # outputs "b"
echo -e "a\tb\tc" |cut -f 3 # outputs "c"
echo -e "a\tb\tc" |cut -f 1,3 # outputs "a\tc"
echo -e "a\tb\tc\td\te" |cut -f 2-4 # outputs "b\tc\td"

You can also specify the output delimiter (--output-delimiter) and get rid of lines not containing any delimiters (-s/--only-delimited)

echo -e "a\tb\tc\td\te" |cut -f 2-4 --output-delimiter=":" # outputs b:c:d

If you are interrested in the first field of your input file simply do...

cut -f 1 file.txt
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