Groovy Question
groovy regex to eliminate desired character & all characters succeeding to desired character?
How to eliminate the desired character & all the other characters succeeding that desired character.
def str1 = "value_of_string*123456"
Here, desired character is
"*""123456"So, after removing them
str1"value_of_string"
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Answer Source
def str1 = "value_of_string*123456"
assert str1.takeWhile { it != '*' } == 'value_of_string'
assert str1.tokenize('*')[0] == 'value_of_string'
assert str1.split("\\*")[0] == 'value_of_string'
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