msqar - 1 year ago 245

Swift Question

I'm trying to understand how a Vector is created in Swift, because when I do CGVectorMake(), tells me to pass a dx and dy (derivative) as a CGFloat.

How can I create a Vector (line) with only that information?

Can anyone explain me ? Like for dummies? I searched in Google but I still couldn't find an easy explanation.

Let's say I would like to create a Vector that goes from point (0,0) to point (5,5).

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Answer Source

There are many possible representations of vectors, one is as the "distance" or "displacement" from one point to another point (compare Euclidean vector: Representations).

In that sense, the vector from (0,0) to (5,5) is *identical* to the
vector from (2,3) to (7, 8), and the vector from point A to point B
can be computed as

```
let pA = CGPoint(x: 2, y: 3) // Point A
let pB = CGPoint(x: 7, y: 8) // Point B
let vecAB = CGVector(dx: pB.x - pA.x, dy: pB.y - pA.y) // Vector from A to B
print(vecAB) // CGVector(dx: 5.0, dy: 5.0)
```

So `dx`

, `dy`

stand for "delta X" and "delta Y", the distance of
the points in x- and y-direction. In the above case, you could
interpret `vecAB`

as "move 5 units in x-direction and 5 units
in y-direction".

A "line segment" from (0, 0) to (5, 5) cannot be represented by a vector alone. You would need two points, or one point and one vector.

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