Dan13_ Dan13_ - 1 year ago 99
HTML Question

How do i recreate a html request header?

I'm currently writing a Java Application that remotely controls my Roku. I found this website and used it to control my Roku. From Chromes developer tools i watched its data traffic and found the html request that controlled the Roku. The Header was this.

POST /keydown/Play HTTP/1.1
Host: 192.xxx.x.82:8060
Connection: keep-alive
Content-Length: 0
Cache-Control: max-age=0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8
Origin: http://remoku.tv
Upgrade-Insecure-Requests: 1
User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/49.0.2623.110 Safari/537.36
Content-Type: application/x-www-form-urlencoded
Referer: http://remoku.tv/
Accept-Encoding: gzip, deflate
Accept-Language: en-US,en;q=0.8

I then tried to recreate this POST request within Java and it ended up looking like this:

HttpURLConnection urlConn;
URL url = new URL("html://192.xxx.x.82:8060/keydown/Play");
urlConn = (HttpURLConnection) url.openConnection();

urlConn.setRequestProperty("Connection", "keep-alive");
urlConn.setRequestProperty("Content-Length", "0");
urlConn.setRequestProperty("Cache-Control", "max-age=0");
urlConn.setRequestProperty("Accept", "text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8");
urlConn.setRequestProperty("Origin", "http://192.xxx.x.254");
urlConn.setRequestProperty("Upgrade-Insecure-Requests", "1");
urlConn.setRequestProperty("User-Agent","Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/49.0.2623.110 Safari/537.36");
urlConn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
urlConn.setRequestProperty("Referer", "http://192.xxx.x.254");
urlConn.setRequestProperty("Accept-Encoding", "gzip, deflate");
urlConn.setRequestProperty("Accept-Language", "en-US,en;q=0.8");

I'm not 100% sure this is the correct way to recreate the request because it does not have the same effect as the the original (working). However, this may be because I changed a few minor details that may have actually be important. So my question to you is if this the correct way to recreate a request and if it is why is it not working? If not what is? Any help is appreciated.

Answer Source

Thanks to tgkprog's comment i edited my code to this:

HttpURLConnection urlConn;
URL url = new URL("http://192.xxx.x.82:8060/keypress/Right");
urlConn = (HttpURLConnection) url.openConnection();

try(DataOutputStream wr = new DataOutputStream(urlConn.getOutputStream())) {


and now it works perfectly and I can control my Roku the problem was i was not using the correct keys in the header as they where not in caps lock in Chrome (edit: they are not needed).