Jed Grant Jed Grant - 1 month ago 33
iOS Question

Open a WKWebview target="_blank" link in Safari using SWIFT

I am trying to get my Hybrid IOS app that uses SWIFT and WKWebviews to open a link that has

target="_blank"
or if the URL contains
http://
,
https://
, or
mailto:
in Mobile Safari.

From this answer I get this code.

func webView(webView: WKWebView!, createWebViewWithConfiguration configuration: WKWebViewConfiguration!, forNavigationAction navigationAction: WKNavigationAction!, windowFeatures: WKWindowFeatures!) -> WKWebView! {
if navigationAction.targetFrame == nil {
webView.loadRequest(navigationAction.request)
}
return nil
}


First, that doesn't do anything for me. Second, I want it to open in a new window. And I found this code that is supposed to do something like that...

if let requestUrl = NSURL(string: "http://www.iSecurityPlus.com") {
UIApplication.sharedApplication().openURL(requestUrl)
}


How do I put these two together and get them to work? What do I need to add to the ViewController declaration to make it work?

Answer

In (from here)

 override func loadView() {
    super.loadView()
    self.webView.navigationDelegate = self 
    self.webView.UIDelegate = self  //must have this
 }

Then add the function (from here, with additions)...

func webView(webView: WKWebView,
    createWebViewWithConfiguration configuration: WKWebViewConfiguration,
    forNavigationAction navigationAction: WKNavigationAction,
    windowFeatures: WKWindowFeatures) -> WKWebView? {
        if navigationAction.targetFrame == nil {
            var url = navigationAction.request.URL
            if url.description.lowercaseString.rangeOfString("http://") != nil || url.description.lowercaseString.rangeOfString("https://") != nil || url.description.lowercaseString.rangeOfString("mailto:") != nil  {
                UIApplication.sharedApplication().openURL(url)
            }
        }
        return nil
}