next2u - 1 year ago 85

PHP Question

I am calling Octave script from PHP and passing parameters to it. But I get the unexpected output.

The PHP code I'm using to pass arguments and call the Octave script is:

`$a=8;`

$b=3;

$cmd = "C:\Octave\Octave4\bin\octave-cli C:\wamp\www\dspace\add.m $a $b";

$ex = passthru($cmd, $op);

var_dump($ex);

My Octave script:

`arglist = argv();`

a = arglist{1};

b = arglist{2};

function f (a,b)

a + b

endfunction

printf(f(a,b));

The output get is:

`ans = 107`

Expected output is:

`11`

How can I fix this?

Answer Source

You are adding the ASCII codes for the character "8" which is 56 and "3" which is 51 so the result is 107. Convert the strings to numbers:

```
arglist = argv();
a = str2num (arglist{1});
b = str2num (arglist{2});
function ret = f (a,b)
ret = a + b;
endfunction
printf("%i", f(a,b));
```