Marcelo Medeiros - 7 months ago 48

Java Question

I am developing a Java (JDK 1.8) application using standard (built in) DSA classes in order to verify digital signatures.

I have data files and the expected signatures stored in text files as shown below:

`// Signature part R:`

4226 3F05 F103 E3BE 59BF 3903 37F8 0375 8802 5D8F.

// Signature part S:

AF21 15B0 16E4 1761 75B8 C7D4 F877 5AB7 26BB AE72.

Note that the signature is expressed in the form of (R,S) pair as described in the FIPS 186-3 NIST Standard.

In order to verify the signature I am calling the method verify(byte[] signature) from java.security.Signature. This method expects a byte array that represents the signature to be verified. However, I do not know how to convert the (R,S) pair into a byte array. Therefore I am not able to verify the signature.

So, I would like to know:

1) Is there a way of converting (R, S) pair into a DSA byte array signature as expected by the verify() method?; Or,

2) Is there a way of getting the R and S values from the Java Signature instance class so that I can compare these values to the ones I have?

Thanks in advance.

EDIT: the solution proposed by @dave_thompson_085 worked pretty well! See below the complete source code:

`// read DSA parameters from file or other means`

BigInteger r = new BigInteger(...);

BigInteger s = new BigInteger(...);

BigInteger p = new BigInteger(...);

BigInteger q = new BigInteger(...);

BigInteger g = new BigInteger(...);

BigInteger y = new BigInteger(...);

// get the public key

KeySpec publicKeySpec = new DSAPublicKeySpec(y, p, q, g);

KeyFactory keyFactory = KeyFactory.getInstance("DSA");

PublicKey publicKey = keyFactory.generatePublic(publicKeySpec);

// read the input file to be checked and update signature

Signature signature = Signature.getInstance("SHA1withDSA");

signature.initVerify(publicKey);

File inputFile = new File(...);

try (BufferedInputStream is = new BufferedInputStream(new FileInputStream(inputFile))) {

byte[] buffer = new byte[1024];

while (is.available() != 0) {

int len = is.read(buffer);

signature.update(buffer, 0, len);

}

}

// convert (r, s) to ASN.1 DER encoding

// assuming you have r and s as !!positive!! BigIntegers

// (if you have unsigned byte[] as shown in your Q,

// use BigInteger r = new BigInteger (1, bytes) etc.

byte[] rb = r.toByteArray();

byte[] sb = s.toByteArray(); // sign-padded if necessary

// these lines are more verbose than necessary to show the structure

// compiler will fold or you can do so yourself

int off = (2 + 2) + rb.length;

int tot = off + (2 - 2) + sb.length;

byte[] der = new byte[tot + 2];

der[0] = 0x30;

der[1] = (byte) (tot & 0xff);

der[2 + 0] = 0x02;

der[2 + 1] = (byte) (rb.length & 0xff);

System.arraycopy(rb, 0, der, 2 + 2, rb.length);

der[off + 0] = 0x02;

der[off + 1] = (byte) (sb.length & 0xff);

System.arraycopy(sb, 0, der, off + 2, sb.length);

// verifies if the signature is valid

boolean isValid = signature.verify(des);

Answer

1A. The form expected by normal Java crypto (and most but not all other uses of DSA, and also ECDSA) is an **ASN.1 DER encoding**. http://crypto.stackexchange.com/a/1797/12642 explains what the difficulties are but doesn't quite tell you how to do it.

1B. If you have or can install the BouncyCastle cryptoprovider jar, it contains a whole set of ASN.1 routines. Or easier it also contains
a low-level primitive `org.bouncycastle.crypto.signers.DSASigner`

with `init`

and `verifySignature(byte[], BigInteger, BigInteger)`

accessible. (But this primitive does not do the hash, so do that yourself first.)

1C. If you must do it yourself with standard crypto:

```
// assuming you have r and s as !!positive!! BigIntegers
// (if you have unsigned byte[] as shown in your Q,
// use BigInteger r = new BigInteger (1, bytes) etc.
byte[] rb = r.toByteArray(), sb = s.toByteArray(); // sign-padded if necessary
// these lines are more verbose than necessary to show the structure
// compiler will fold or you can do so yourself
int off = (2+2)+rb.length, tot = off+(2-2)+sb.length;
byte[] der = new byte[tot+2];
der[0] = 0x30; der[1] = tot;
der[2+0] = 0x02; der[2+1] = rb.length; System.arraycopy(rb,0, der,2+2, rb.length);
der[off+0] = 0x02; der[off+1] = sb.length; System.arraycopy(sb,0, der,off+2, sb.length);
```

2. You cannot verify a standard DSA signature by comparing r and s. As you should know from reading FIPS186-3 sections 4.5 and 4.6 signatures are randomized; computing two (or more) signatures for the same message gives a different (r,s) pair every time -- unless you repeat enough times to hit the same k, which on average is 2^159 tries for older 1024/160 groups/keys, more for newer/larger ones. If you have a million computers each of which can do a million tries per second, this will still take about 16,000,000,000,000,000,000,000,000,000 years.

Source (Stackoverflow)