Mike - 1 year ago 121

C++ Question

Hello i have an issue with a returning value of the glm lookAt function. When i am executing in debug mode, i get at this point

` ... Result[3][2] = dot(f, eye); ...`

1 0 0 0

0 1 0 0

0 0 1 0

0 0 0 1

but i get this one:

1 -0 0 -0

-0 1 -0 -0

0 0 1 -2

0 0 0 1

My code is:

`struct camera {`

vec3 position = vec3(0.0f); // position of the camera

vec3 view_direction = vec3(0.0f); // forward vector (orientation)

vec3 side = vec3(0.0f); // right vector (side)

vec3 up = vec3(0.0f, 1.0f, 0.0f); // up vector

float speed = 0.1;

float yaw = 0.0f; // y-rotation

float cam_yaw_speed = 10.0f; // 10 degrees per second

float pitch = 0.0f; // x-rotation

float roll = 0.0f;

...

// calculate the orientation vector (forward)

vec3 getOrientation(vec3 vantage_point) {

// calc the difference and normalize the resulting vector

vec3 result = vantage_point - position;

result = normalize(result);

return result;

}

// calculate the right (side) vector of the camera, by given orientation(forward) and up vectors

mat4 look_at_point(vec3 vantage_point) {

view_direction = getOrientation(vantage_point);

// calculate the lookat matrix

return lookAt(position, position + view_direction, up);

}

};

I have tryied to figure out how to manage this problem but i still have no idea. Can someone help me?

The main function where i am executing the main_cam.look_at_point(vantage_point) function is showed below:

`...`

GLfloat points[] = {

0.0f, 0.5f, 0.0f,

0.5f, 0.0f, 0.0f,

-0.5f, 0.0f, 0.0f };

float speed = 1.0f; // move at 1 unit per second

float last_position = 0.0f;

// init camera

main_cam.position = vec3(0.0f, 0.0f, 2.0f); // don't start at zero, or will be too close

main_cam.speed = 1.0f; // 1 unit per second

main_cam.cam_yaw_speed = 10.0f; // 10 degrees per second

vec3 vantage_point = vec3(0.0f, 0.0f, 0.0f);

mat4 T = translate(mat4(1.0), main_cam.position);

//mat4 R = rotate(mat4(), -main_cam.yaw, vec3(0.0, 1.0, 0.0));

mat4 R = main_cam.look_at_point(vantage_point);

mat4 view_matrix = R * T;

// input variables

float near = 0.1f; // clipping plane

float far = 100.0f; // clipping plane

float fov = 67.0f * ONE_DEG_IN_RAD; // convert 67 degrees to radians

float aspect = (float)g_gl_width / (float)g_gl_height; // aspect ratio

mat4 proj_matrix = perspective(fov, aspect, near, far);

use_shader_program(shader_program);

set_uniform_matrix4fv(shader_program, "view", 1, GL_FALSE, &view_matrix[0][0]);

set_uniform_matrix4fv(shader_program, "proj", 1, GL_FALSE, &proj_matrix[0][0]);

...

Testing with the rotate function of glm the triangle is shown right.

Triangle shown with the rotate function of glm

Recommended for you: Get network issues from **WhatsUp Gold**. **Not end users.**

Answer Source

I suspect that the problem is here:

```
mat4 view_matrix = R * T; // <---
```

The matrix returned by `look_at`

already does the translation.

Try manually applying the transformation on the (0,0,0) point that is inside your triangle. `T`

will translate it to (0,0,2), but now it coincides with the camera, so `R`

will send it back into (0,0,0). Now you get a division by zero accident in the projective divide.

So remove the multiplication by `T`

:

```
mat4 view_matrix = R;
```

Now (0,0,0) will be mapped to (0,0,-2), which is in the direction camera is looking. (In camera space the center-of-projection is at (0,0,0) and the camera is looking towards the negative Z direction).

Recommended from our users: **Dynamic Network Monitoring from WhatsUp Gold from IPSwitch**. ** Free Download**