thaweatherman thaweatherman -4 years ago 171
Python Question

XPath invalid expression when tag name has curly braces

The name of the tag I am trying to get to is

. Conveniently every tag is prefixed with that lovely reference to the whitehat website. Unfortunately the
doesn't like it. I am currently trying
which should get me to the right node. However lxml keeps saying

File "", line 23, in <module>
for s in vuln_root[0].xpath('//\{\}description'):
File "lxml.etree.pyx", line 1509, in lxml.etree._Element.xpath (src/lxml/lxml.etree.c:50725)
File "xpath.pxi", line 318, in lxml.etree.XPathElementEvaluator.__call__ (src/lxml/lxml.etree.c:146020)
File "xpath.pxi", line 238, in lxml.etree._XPathEvaluatorBase._handle_result (src/lxml/lxml.etree.c:145028)
File "xpath.pxi", line 224, in lxml.etree._XPathEvaluatorBase._raise_eval_error (src/lxml/lxml.etree.c:144883)
lxml.etree.XPathEvalError: Invalid expression

How can I get around this awful tag naming in my xpath? Thanks

Answer Source

The easiest approach here is to just map the namespace.

    namespaces={'vuln': ''})
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