Narusan - 1 month ago 4

Python Question

Suppose I have a 4x4 matrix that looks like the following:

`[[0, 0, 0, 0]`

[0, 0, 1, 0]

[0, 0, 0, 0]

[0, 0, 0, 0]]

I want to write a function that takes all 4 surrounding fields of the one and turns them into a 1 as well.

The above matrix would become:

`[[0, 0, 1, 0]`

[0, 1, 1, 1]

[0, 0, 1, 0]

[0, 0, 0, 0]]

I know that this is possible using if-statements, but I really want to optimize my code.

The matrix only contains 0's and 1's. If the 1 is at the edge of the matrix, the 1's should not wrap around, i.e. if the most left field is a 1, the most right field still stays at 0. Also, I am using Python 3.5

Is there a more mathematical or concise way to do this?

Answer

This looks like binary dilation. There's a function available in SciPy that implements this efficiently:

```
>>> from scipy.ndimage import binary_dilation
>>> x
array([[0, 0, 0, 0],
[0, 0, 1, 0],
[0, 0, 0, 0],
[0, 0, 0, 0]])
>>> binary_dilation(x).astype(int)
array([[0, 0, 1, 0],
[0, 1, 1, 1],
[0, 0, 1, 0],
[0, 0, 0, 0]])
```

1s at the edges are handled as you've specified they should be (i.e. no wrapping).

See the documentation for further options and arguments.

Source (Stackoverflow)

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