Jonathan Jonathan - 1 year ago 167
JSON Question

Posting JSON from iOS to PHP

I've been trying to send JSON data from an iOS app to a mySQL database via a php page. For some reason, my POST data is not available in the php page.

- (IBAction)jsonSet:(id)sender {
NSDictionary *dict = [NSDictionary dictionaryWithObjectsAndKeys:@"firstvalue", @"firstkey", @"secondvalue", @"secondkey", nil];
NSData *result =[NSJSONSerialization dataWithJSONObject:dict options:0 error:&error];
NSURL *url = [NSURL URLWithString:@""];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setValue:[NSString stringWithFormat:@"%d", jsonRequestData.length] forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody:jsonRequestData];

NSURLResponse *response = nil;
NSError *error = nil;

NSData *result = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];

I know the php page gets called, and writing to the database is confirmed,

The first couple of lines in my php file grab the POST data

// Put parameters into local variables
$email = $_POST["firstkey"];

but for some reason, $email is also an empty string. I have a feeling the problem is in the iOS code, because i can use to test my page and I can confirm it works (only if I exclude the Content-type and Content-Length fields)

Thanks for your help

Answer Source

PHP does not decode JSON POST body to $_POST array (so you can't use $email = $_POST["firstkey"];). You need to extract incoming data to array (or object). Lines of code for you PHP-file:

$jsonString = file_get_contents('php://input');
$jsonArray = json_decode($json_string, true);

$jsonArray will represent the JSON structure you sent.

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