vicky96 vicky96 - 4 years ago 239
Python Question

Python - What happens when I write statements in the interpreter without 'print'?

I just started learning python 2.7.11 from the docs.
I was doing the examples which were given in there, but got confused when

were introduced. I got confused about the how backslashes are being displayed as output. This is related to character escaping but till now I just used
for backspace,
for new line,
for a backslash

This is what I am talking about:

enter image description here

There are four different cases:

  1. using neither

  2. using
    but not

  3. using
    but not

  4. using both

and all of them give different outputs. I can't get my head around what's actually happening in all the four cases.

Answer Source

There's no connection between the two, necessarily. r introduces a raw string literal, which doesn't parse escape codes, which means that a \ between the quotes will be an actual \ character in the string data.

print will print out the actual string, while just typing a string literal at the >>> prompt will cause Python to implicitly print the value of the string, but it will be printed as a string literal (with special characters escaped), so you could take it, paste it back into >>> and get the same string.

Edit: repr() was mentioned in some of the comments. Basically, it's meant to return a representation of an object that can be parsed back into an equivalent object, whereas str() is aimed more towards a human-readable description. For built-in objects, both are predefined as appropriate, while for user objects, you can define them by defining the special methods __repr__() and __str__().

>>> obj will print out repr(obj), while print obj will print the value of str(obj).

>>> class Foo(object):
...     def __str__(self):
...             return "str of Foo"
...     def __repr__(self):
...             return "Foo()"
>>> f = Foo()
>>> f
>>> print f
str of Foo
>>> eval(repr(f))

Also, regarding the \es, it would also be worth noting that Python will ignore escape sequences it doesn't know:

>>> [c for c in '\w']
['\\', 'w']
>>> [c for c in '\n']

\n becomes a newline character, while \w remains a backslash followed by a w.

For example, in 'hello\\\world', the first \ escapes the second one, and the third one is left alone because it's followed by a w.

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