Zach Zach - 6 months ago 22
R Question

Fastest way to replace NAs in a large data.table

I have a large data.table, with many missing values scattered throughout its ~200k rows and 200 columns. I would like to re code those NA values to zeros as efficiently as possible.

I see two options:

1: Convert to a data.frame, and use something like this

2: Some kind of cool data.table sub setting command

I'll be happy with a fairly efficient solution of type 1. Converting to a data.frame and then back to a data.table won't take too long.


Here's a solution using data.table's := operator, building on Andrie and Ramnath's answers.

require(data.table)  # v1.6.6
require(gdata)       # v2.8.2

dt1 = create_dt(2e5, 200, 0.1)
[1] 200000    200    # more columns than Ramnath's answer which had 5 not 200

f_andrie = function(dt) remove_na(dt)

f_gdata = function(dt, un = 0) gdata::NAToUnknown(dt, un)

f_dowle = function(dt) {     # see EDIT later for more elegant solution
    na.replace = function(v,value=0) { v[] = value; v }
    for (i in names(dt))

system.time(a_gdata = f_gdata(dt1)) 
   user  system elapsed 
 18.805  12.301 134.985 

system.time(a_andrie = f_andrie(dt1))
Error: cannot allocate vector of size 305.2 Mb
Timing stopped at: 14.541 7.764 68.285 

  user  system elapsed 
 7.452   4.144  19.590     # EDIT has faster than this

identical(a_gdata, dt1)   
[1] TRUE

Note that f_dowle updated dt1 by reference. If a local copy is required then an explicit call to the copy function is needed to make a local copy of the whole dataset. data.table's setkey, key<- and := do not copy-on-write.

Next, let's see where f_dowle is spending its time.

                  self.time self.pct total.time total.pct
"na.replace"           5.10    49.71       6.62     64.52
"[.data.table"         2.48    24.17       9.86     96.10
""                1.52    14.81       1.52     14.81
"gc"                   0.22     2.14       0.22      2.14
"unique"               0.14     1.36       0.16      1.56
... snip ...

There, I would focus on na.replace and, where there are a few vector copies and vector scans. Those can fairly easily be eliminated by writing a small na.replace C function that updates NA by reference in the vector. That would at least halve the 20 seconds I think. Does such a function exist in any R package?

The reason f_andrie fails may be because it copies the whole of dt1, or creates a logical matrix as big as the whole of dt1, a few times. The other 2 methods work on one column at a time (although I only briefly looked at NAToUnknown).

EDIT (more elegant solution as requested by Ramnath in comments) :

f_dowle2 = function(DT) {
    for (i in names(DT))

  user  system elapsed 
 6.468   0.760   7.250   # faster, too

identical(a_gdata, dt1)   
[1] TRUE

I wish I did it that way to start with!

EDIT2 (over 1 year later, now)

There is also set(). This can be faster if there are a lot of column being looped through, as it avoids the (small) overhead of calling [,:=,] in a loop. set is a loopable :=. See ?set.

f_dowle3 = function(DT) {
    # either of the following for loops

    # by name :
    for (j in names(DT))

    # or by number (slightly faster than by name) :
    for (j in seq_len(ncol(DT)))