IEnumerable IEnumerable - 1 month ago 16
jQuery Question

How to call a function inside $(document).ready

Im trying to debug my web app that uses

jQuery.


In firebug im calling functions inside the $(document).ready..

function val() { console.log('validated outside doc.ready'); }
$(document).ready(function()
{

console.log('document ready...');

function validate() { console.log('validated!'); }
}


In firebug console I type
validate()
and it says its not a function

If i type
val()
it works fine.

How do i call validate from the console ?

Answer

You are not calling a function like that, you just define the function.

The correct approach is to define the function outside document.ready and call it inside:

// We define the function
function validate(){
  console.log('validated!');
}

$(document).ready(function(){
  // we call the function
  validate();
});

Another option is to self invoke the function like that:

$(document).ready(function(){
   // we define and invoke a function
   (function(){
     console.log('validated!');
   })();
});